25t-9.8t^2=0

Solution for 25t-9.8t^2=0 equation:

25t-9.8t^2=0

a = -9.8; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·(-9.8)·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*-9.8}=\frac{-50}{-19.6}
=2+6/10.888888888889
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*-9.8}=\frac{0}{-19.6}
=0
$